At 11 a.m., Joe started driving at 50 miles per hour. Fifteen minutes later, Beth started driving along the same highway in the same direction as Joe at 65 miles per hour. At what time will Beth catch up with Joe?

If “t” represents the number of hours, from 11 am, when Beth catches up with Joe. The time that Beth will have to drive to catch up with Joe, then, is t - ¼. Beth starts a quarter of an hour late. When Beth catches up with Joe, they would have traveled the same distance. So: 50 t = 65 (t - 1/4) Then solve for t 50t = 65t - 65/4 t = 65/60 = 1.083 hours = 1 hour and 5 minutes Beth will catch up with Joe at 11 am + 1 hour , 5 minutes = 12:05 pm

Asked by Tom Tennant · Last updated 5 years ago · 1.6K views · SOURCE