Your new car can go 400 miles on eight gallons of gas. How far can the car go with only one gallon?

worth 10 pts

This is a ratio word problem. First, find the ratio of the number of miles the car can travel, to the number of gallons of gas the car has in the tank: 400/8. Then, write the ratio in its simplest form: 50/1. You can find this ratio by dividing both the numerator and denominator by 8.

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- 52 miles
- 55 miles
- 50 miles
- 58 miles

A house has four rooms. Each room has three lamps. How many lamps are in the house?

worth 10 pts

Use multiplication to find the answer. 4 rooms x 3 lamps per room. 4 x 3 = 12

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- 10
- 9
- 11
- 12

The original price of a shirt was $20. It was decreased to $15 . What is the percent decrease of the price of this shirt?

worth 10 pts

Start with the absolute decrease: 20 - 15 = $5. Then find the percent decrease by dividing the absolute decrease by the original price: 5 / 20 = 0.25

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- 50 percent
- 25 percent
- 14 percent
- 30 percent

It takes John 25 minutes to walk to the car park and 45 to drive to work. At what time should he get out of the house in order to get to work at 9:00 a.m.?

worth 10 pts

First, figure out how long it takes John to commute. 25 minutes walking plus 45 minutes driving. 25 + 45 = 70 minutes. Now turn the clock back 70 minutes from 9 a.m. 60 minutes makes it 8 a.m. and another 10 makes it 7:50.

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- 8:50 a.m.
- 7:50 a.m.
- 5:50 a.m.
- 6:51 a.m.

Jamie makes $1,000 dollars per week. What is his annual salary?

worth 10 pts

First find the number of weeks in a year. 1 year = 52 weeks. Then multiply how much Jamie makes each week by 52: 1,000 x 52 = 52,000.

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- $25,000
- $54,000
- $26,000
- $52,000

Mr. Gloth’s new hybrid car gets him 60 miles per gallon. If Mr. Gloth’s 14-gallon tank is full, how far can he go without having to stop for gas?

worth 10 pts

Using multiplication, we find out how far Mr. Gloth has driven: 60 miles x 14 gallons = 840 miles.

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- 810 miles
- 820 miles
- 840 miles
- 830 miles

Tower A is about 1,063 feet high. Tower B is about 305 feet tall. If you could put Tower B on top of Tower A, how tall would the two be?

worth 10 pts

Another easy one to keep you on track! Stack the heights and add them up. 1,063 + 305 = 1,368

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- 1,368 feet
- 1,396 feet
- 1,118 feet
- 790 feet

Kim can walk 4 miles in one hour. How long does it take Kim to walk 18 miles?

worth 10 pts

Divide the total number of miles by the number of miles Kim can walk in an hour: 18 / 4 = 4.5.

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- 5.5 hours
- 3.5 hours
- 4.5 hours
- 4.75 hours

Ashley bought a big bag of candy. The bag had 102 blue candies, 100 red candies and 94 green candies. How many candies were there in total?

worth 10 pts

Add the three types of candy together. 102 + 100 + 94. Delicious.

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- 278
- 296
- 298
- 256

There are 60 minutes in 1 hour. How many minutes are there in 12 hours?

worth 10 pts

You could use addition to solve this problem, but do you really want to tackle this equation?
60+60+60+60+60+60+60+60+60+60+60+60 = 720
No. Multiplication makes it easier.
60 × 12 = 720

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- 710
- 740
- 730
- 720

Owen sells collector shoes for a living. On Monday his revenue was $150. On Tuesday, his revenue was $100. Finally, on Wednesday, his revenue was $50. How much has Owen made so far this week?

worth 10 pts

Thought we’d go easy on you with this one. Simply add the sum of each day’s revenue.
$150 + $100 + $50 = 300 dollars

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- $100
- $10
- $300
- $550

Tim caught 6 ladybugs, Ali caught 7, and Jon caught 5. The children put some of their ladybugs in a big jar. The jar then had 8 ladybugs. How many ladybugs were not placed in the jar?

worth 10 pts

First figure out how many ladybugs were caught. 6 + 7 + 5 = 18. Then subtract the total from the number of ladybugs in the jar. 18 - 8 = 10. 10 ladybugs.

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- 12
- 9
- 10
- 8

A large box contains 18 small boxes and each small box contains 25 chocolate bars. How many chocolate bars are in the large box?

worth 10 pts

Multiply the number of small boxes by the number of chocolate bars in each. 18 x 25 = 450.

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- 456
- 450
- 350
- 220

Ryan had a stack of 1,200 books in his shop. He sold 75 on Monday, 50 on Tuesday, 64 on Wednesday, 78 on Thursday and 135 on Friday. What percentage of the books were not sold?

worth 10 pts

Start by letting N equal the total number of books sold. So: N = 75 + 50 + 64 + 78 + 135 = 402
Let M be the books NOT sold: M = 1,200 - N = 1200 - 402 = 798
Solve the percentage: Books not sold / total number of books = 798/1200 = 0.665 = 66.5%

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- 45.5 percent
- 90 percent
- 13.7 percent
- 66.5 percent

A family had dinner in a restaurant and paid $30 for food. They also had to pay 9.5 percent sale tax and 10 percent for the tip. How much did they pay for dinner?

worth 10 pts

Following the equation, find the final sum: $30 + (9.5% * 30) + (10% * 30) = $35.85

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- $38.58
- $33.75
- $35.85
- $26.85

A test has 20 questions. If Jeri gets 80 percent correct, how many questions did she miss?

worth 10 pts

Start by determining the percentage of correct answers Jeri made, so 80 percent of 20 or 80/100 × 20 = 0.80 × 20 = 16. Sixteen is the percentage, or what you get when you take the percent of a number. Now that we know how many questions Jeri got correct - 16 - we can figure out how many she missed: 20 − 16 = 4

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- 3
- 2
- 5
- 4

A 4-digit number has a six in the thousands place, a nine in the ones place and two zeros elsewhere. What is the number?

worth 10 pts

This is a simple number placement word problem. Place the six in the thousands place (6,000), the nine in the ones place (6,009) and keep the zeros in between.

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- 6,009
- 6,090
- 9,600
- 9,696

A number has five in the tens position and two more ones than tens. What is the number?

worth 10 pts

Two more ones than tens is equal to 5 + 2 or 7. Therefore, the number has 5 tens and 7 ones. The number is 57.

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- 27
- 67
- 57
- 17

Which three numbers have the same answer whether they’re added or multiplied together?

worth 10 pts

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- 11, 12, and 13
- 3, 6, and 9
- 2, 4, and 6
- 1, 2, and 3

When Owen measured his height, he discovered he was 6 feet tall. Thinking that was a mistake, he measured again and found that he was actually 5 feet tall. What is the percent error Owen made the first time he measured his height?

worth 10 pts

Use the percent error equation to solve this problem. Percent error = (amount of error/accepted value). Find the amount of error: 6 - 5 = 1. Then take the accepted value; 5 feet in this case. So, percent error = 1/5
Convert 1/5 to a percent, or 20 percent.

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- 20 percent
- 40 percent
- 50 percent
- 30 percent

A rectangular garden in Mrs Jewett’s house has a length of 100 meters and a width of 50 meters. She plans to build a square swimming pool inside the garden. Find the length of one side of the swimming pool if the remaining area (not occupied by the pool) is equal to one half the area of the rectangular garden.

worth 10 pts

Make “x” represent the side of the swimming pool. If the area not covered by the swimming pool is half the rectangular garden, then the other half is covered by the swimming pool whose area is x2. So:
x2 = (1/2) 100*50 = 2500
Solve for x
x = 50 meters , side of the swimming pool

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- 40 m
- 50 m
- 60 m
- 70 m

The numbers 2 , 3 , 5 and x have an average equal to 4. What is x?

worth 10 pts

The average of 2 , 3 , 5 and x is given by (2 + 3 + 5 + x) / 4 and it is known and equal to 4.
So (2 + 3 + 5 + x) / 4 = 4
Solve the above equation for x
x = 6

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- 6
- 5
- 9
- 7

In one night, a movie theater sells tickets for $6,450. Each ticket costs $15. How many people purchased a ticket?

worth 10 pts

? × 15 = 6450 where the question mark represents the number of people who purchased a ticket.
6,450 ÷ 15 = 430, so 430 people purchased a ticket.

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- 430
- 410
- 440
- 420

Pump A can fill a tank of water in 5 hours. Pump B can fill the same tank in 8 hours. How long does it take the two pumps working together to fill the tank? (round your answer to the nearest minute).

worth 10 pts

We know that in an hour pump A can fill one-fifth of a tank and pump B can fill one-eighth of the same tank. So we can find out how much both pumps can fill in an hour, while working together by using the equation: 1/5 + 1/8 = 13 / 40 of a tank. Now that we know the rate, 13/40, we can find the time it takes to fill them:
(13/40) t = 1
t = 40 / 13 = 39/13 + 1/13 hours
= 3 hours and (1/13)*60 minutes
= 3 hours 5 minutes (rounded to the nearest minute)

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- 3 hours, 5 mins
- 30 mins
- 6 hours, 15 mins
- 1 hours

24 students in a class took a literature test. If 18 students passed the test, what percent did NOT pass?

worth 10 pts

First, determine the number of students who flunked the test: 24 − 18 = 6. Then follow this equation: x% of 24 = 6 or x% times 24 = 6
To get x%, just divide 6 by 24
6/24 = 0.25 = 25/100 = 25 percent

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- 12.5 percent
- 100 percent
- 25 percent
- 50 percent

There is a three digit number. The second digit is four times as big as the third digit, while the first digit is three less than the second digit. What is the number?

worth 10 pts

Four is 4x larger than one. One is three less than four. It all fits!

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- 142
- 342
- 151
- 141

The area of a rectangular field is equal to 300 square meters. Its perimeter is equal to 70 meters. Find the width and length of this rectangle.

worth 10 pts

L × W = 300 : area , L is the length and W is the width.
2 L + 2 W = 70 : perimeter
L = 35 - w : solve for L
(35 - W) × W = 300 : substitute in the area equation
W = 15 and L = 20 : solve for W and find L using L = 35 - w.

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- W = 16 and L = 22
- W = 15 and L = 22
- W = 18 and L = 20
- W = 15 and L = 20

In a group of 120 people, 90 have an age of more 30 years, and the others have an age of less than 20 years. If a person is selected at random from this group, what is the probability the person's age is less than 20?

worth 10 pts

First solve for the number of people whose age is less than 20 by subtracting 90 from 120:
120 - 90 = 30. Then show the probability (P) that a person selected at random from the group is less than 20 is given by dividing 30 by 120: 30 / 120 = 0.25.

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- 27 percent chance
- 25 percent chance
- 30 percent chance
- 35 percent chance

Alan bought a total of 20 game cards, some of which cost $0.25 each and some of which cost $0.15 each. If Alan spent $4.20 to buy the cards, how many cards of each type did he buy?

worth 10 pts

Start by assigning X as the number of cards that cost $0.25 each and Y as the number of cards that cost $0.15. Knowing that the total number of cards equals 20, we can write the equation: X + Y = 20
Now we can say that the X cards cost: 0.25 X
And the Y cards cost: 0.15 Y
If the total cost for the cards is $4.20, we can say: 0.25 X + 0.15 Y = 4.2
Now solve the system of equations:
X + Y = 20
0.25 X + 0.15 Y = 4.2
The first equation gives Y = 20 - X. Substitute Y by 20 - X in the second equation and solve
0.25 X + 0.15 (20 - X) = 4.2
X(0.25 - 0.15) + 3 = 4.2
0.1 X = 1.2
X = 12 and Y = 20 - 12 = 8

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- 12 $0.25 cards and 8 $0.15 cards
- 11 $0.25 cards and 8 $0.15 cards
- 12 $0.25 cards and 9 $0.15 cards
- 11 $0.25 cards and 10 $0.15 cards

A literature test has 30 questions. Six of those questions ask about character development in chapter 6. What is the ratio of questions from chapter 6 to the other questions on the test?

worth 10 pts

Simply find the number of question on the test that are not from chapter 6, or 30 - 6. Now you can write the ratio: 6:24

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- 6:32
- 6:26
- 6:14
- 6:24

Suppose a math class starts at the beginning of the school year with 12 boys and 8 girls. However, after school resumes in January, 6 new boys and 4 new girls came to the class. Is the ratio of boys to total number of students in the class still the same?

worth 10 pts

To compare, first find out what the ratio of boys to students is at the beginning of the school year: 12/8 or, in the simplest form, 3/2. Once school resumes in January, that ratio becomes 18/12 - (12 + 6)/(8 + 4) - or 3/2 in simplest form.

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- Yes
- No

Jim, Carla and Tommy are members of the same family. Carla is 5 years older than Jim. Tommy is 6 years older than Carla. The sum of their three ages is 31 years. How old are each one of the children?

worth 10 pts

Start by figuring out 3 numbers that equal 31, once you know those, check and see if they satisfy the other requirements like 5, 10, and 16 do.

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- Jim: 5 years , Carla: 10 years , Tommy: 17 years
- Jim: 6 years , Carla: 10 years , Tommy: 16 years
- Jim: 5 years , Carla: 11 years , Tommy: 16 years
- Jim: 5 years , Carla: 10 years , Tommy: 16 years

How many minutes are in one week?

worth 10 pts

First find out how many minutes are in a day. If there are 60 minutes in one hour and 24 hours in a day, then 60 x 24 = 1,440 minutes in a day. Now multiply the number of minutes in a day by the number of days in a week: 1,440 x 7 = 10,080 minutes.

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- 10,080
- 1,440
- 100,800
- 525,600

The division of a whole number N by 13 gives a quotient of 15 and a remainder of 2. Find N.

worth 10 pts

According to the division process of whole numbers, N can be written, using multiplication, as follows: N = quotient × divisor + remainder = 15 × 13 + 2 = 197

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- N=197
- N=198
- N=193
- N=195

An electric motor makes 3,000 revolutions per minute. How many degrees does it rotate in one second?

worth 10 pts

The motor rotates 18,000 degrees in one second. Find this by multiplying the number of revolutions - 3,000 - by the number of degrees - 360 - and then divide by 60 seconds. 3000 × 360 / 60 = 18,000.

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- 9,000 degrees
- 19,000 degrees
- 18,000 degrees
- 20,000 degrees

Can you find the area of a trapezoid only by knowing that the parallel sides are 12 and 23 centimeters long, respectively?

worth 10 pts

The area A of a trapezoid is given by
A = (1/2) height *(base1 + base2)
The two bases are given as 12 and 23 cm, however, the height is not given and therefore there is not enough information to find the area of the trapezoid.

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- Yes
- No

A car is traveling 75 kilometers per hour. How many meters does the car travel in one minute?

worth 10 pts

Start with 60 minutes and also convert kilometers into meters (1 km = 1000 m) and simplify:
75 kilometers per hour = 75 km/hr = (75 × 1000 meters) / (60 minutes) = 1,250 meters / minute

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- 1,230
- 1,350
- 1,320
- 1,250

At 11 a.m., Joe started driving at 50 miles per hour. Fifteen minutes later, Beth started driving along the same highway in the same direction as Joe at 65 miles per hour. At what time will Beth catch up with Joe?

worth 10 pts

If “t” represents the number of hours, from 11 am, when Beth catches up with Joe. The time that Beth will have to drive to catch up with Joe, then, is t - ¼.
Beth starts a quarter of an hour late. When Beth catches up with Joe, they would have traveled the same distance. So:
50 t = 65 (t - 1/4)
Then solve for t
50t = 65t - 65/4
t = 65/60 = 1.083 hours = 1 hour and 5 minutes
Beth will catch up with Joe at
11 am + 1 hour , 5 minutes = 12:05 pm

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- 12:08 p.m.
- 12:05 p.m.
- 11:15 p.m.
- 12:25 p.m.

Martha, Peter, and Kenneth have a total of $82 in their wallets. Martha has $10 more than Peter. Kenneth has 2 times what Martha has. How much do they have in their wallets?

worth 10 pts

Start by creating an equation that says Martha(m), Peter(p), and Kenneth(k) have $82 in total.
m + p + k = 82
Next substitute in information so that you replace all but one variable. "Martha has $10 more than Peter" --> that means we can substitute m for p + 10.
(p + 10) + p + k = 82
Then "Kenneth has 2 times what Martha has" --> k = 2 * m = 2 * (p+10)
(p + 10) + p + 2 * (p + 10) = 82
p + 10 + p + 2p + 20 = 82
4p + 30 = 82
4p = 52
p = 13
Peter has $13 which means Martha has $23 ($13 + $10) and Kenneth has $46 (2 times Martha's, $23).

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- Peter = $14, Martha = $24 and Kenneth = $44
- Peter = $18, Martha = $33 and Kenneth = $46
- Peter = $13, Martha = $24 and Kenneth = $46
- Peter = $13, Martha = $23 and Kenneth = $46

A six-sided die is rolled once. What is the probability that the number rolled is an even number greater than 2?

worth 10 pts

While there are three even numbers on a die - two, four and six - only four and six are greater than two. Find the probability that one of the six possible numbers is an even number greater than two by dividing the number of possibilities by 6, or: 2 / 6 = 1 / 3.

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- 17 percent
- 50 percent
- 100 percent
- 33 percent

Sally is 54 years old and her mother is 80, how many years ago was Sally’s mother three times older than Sally?

worth 10 pts

Sally’s mother would be 39 at the time and Sally would be 13. 13 x 3 = 39.

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- 51
- 52
- 42
- 41

Steve invested $5,000 for two years. The rate of annual interest in the first year was 7 percent, and was 8.5 percent in the second year. How much interest did Steve earn at the end of the two year period?

worth 10 pts

First solve for the interest gained at the end of the first year: 7 percent * 5,000 = $350
Then solve for second year interest: 8.5 percent * (5000 + 350) = $454.75
Then add the two totals to find total interest at the end of the two year period.

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- $704.75
- $808.75
- $780.75
- $804.75

At 10:00 a.m., Train A left the station, and an hour later Train B left the same station on a parallel track. If Train A traveled at a constant speed of 60 miles per hour and Train B at 80 miles per hour, then at what time did train B pass train A?

worth 10 pts

First, consider what the question is really asking. If the question is “at what time did Train B pass Train A.” The means the answer can be found by understanding when Train B passes Train A, which is when they have traveled the same distance. Then use the information given - the train speed and when they left the station - to calculate the distance, or: speed = distance/time.
To find distance, rearrange the equation: distance = speed(time)

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- 3 p.m.
- 2:30 p.m.
- 2 p.m.
- 2:15 p.m.

Julie invested one part of her $10,000 annual salary at 7.5 percent per year. The second part she invested at 8.5 percent per year. Her income from the two investment was $820. How much did she invest at each rate?

worth 10 pts

Let x and y be the amount invested at 7.5 percent and 8.5 percent respectively.
Income = $820 = 7.5% * x + 8.5% * y
The total amount invested is also known: 10,000 = x + y
Solve the system of the equations to find x and y: x = $3000 and y = $7000

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- $2,500 and $7,500
- $5,000 and $5,000
- $3,000 and $7,000
- $1,000 and $9,000

If a tire rotates at 400 revolutions per minute when the car is traveling 72km/h, what is the circumference of the tire?

worth 10 pts

Start by determining the number of revolutions in an hour: 400 rev / minute = 400 × 60 rev / 60 minutes = 24,000 rev / hour. Now take that number, 24,000, and find for C, the circumference: 24,000 × C = 72,000 m, where C = 3 meters.

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- 3 meters
- 6 meters
- 2 meters
- 5 meters

In a bag full of small balls, 1/4 of these balls are green, 1/8 are blue, 1/12 are yellow and the remaining 26 white. How many balls are blue?

worth 10 pts

First find the fraction of green, blue and yellow balls: 1/4 + 1/8 + 1/12 = 6 / 24 + 3 / 24 + 2 / 24 , common denominator = 11 / 24 , add numerators
The fraction of white balls is given by: 24 / 24 - 11 / 24 = 13 / 24 So the fraction 13 / 24 corresponds to 26 balls.
If x is the total number of balls then (13 / 24) of x = 26 balls or (13 / 24) × x = 26
x = 26 × (24 / 13) = 48 , total number of balls
The fraction of blue balls is 1 / 8 of x. The number of blue balls is given by (1 / 8) of 48 = 6 balls.

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- 6 balls are blue
- 5 balls are blue
- 7 balls are blue
- 8 balls are blue

How many inches are in 2,000 millimeters? (Please round your answer to the nearest hundredth of an inch)

worth 10 pts

Know the conversion for inches to millimeters: one inch equals 25.4 mm. Then let x inches be the same as 1000 mm
x = 1 inch * 2000 mm / 25.4 mm = 78.74 inches

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- 78.74 inches
- 179.74 inches
- 86.74 inches
- 67.74 inches

A car travels from point A to point B at 40 mph then returns, using the same road, from point B to point A at 60 mph. What is the average speed for the round trip?

worth 10 pts

Find this answer by calculating total distance divided by total time.
If x is the distance from A to B, then the total distance is equal to 2x (away and return). The total T time is equal to time t1 = x / 40 from A to B (away) plus t2 = x / 60 from B to A (return). Hence
T = x / 40 + x / 60 = 100 x / 2400 = x / 24
The average speed is given by: 2x / (x/24) = 48 mph

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- 100 mph
- 50 mph
- 48 mph
- 45 mph

A is a constant. Find A such that the equation 2x + 1 = 2A + 3(x + A) has a solution at x = 2.

worth 10 pts

Substitute x by 2 in the given equation: 2(2)+ 1 = 2A + 3(2 + A)
Solve for A
A = - 1 / 5

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- - 1/8
- - 1/6
- - 1/2
- - 1/5

What three-digit number has the number five as its digit in the tens place and the digit in the hundreds place twice as big as the digit in the ones place?

worth 10 pts

All four answers are correct. To solve the problem start by determining that the number has three digits and the digit in the middle is 5, or a5b.
Then solve for a and b:
a = 8 and b = 4
a = 6 and b = 3
a = 4 and b = 2
a = 2 and b =1

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- 854
- 653
- 452
- 251

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About This Quiz

Quiz Updated: July 1, 2019

What a brave soul, taking on this math test. It is certainly not for the faint of heart. Fifty challenging questions that are sure to give you flashbacks to high school math exams. If you know a little basic math - and a little algebra and geometry - you should do just fine.

Word problems are nothing new. Math maniacs were challengings themselves with words and numbers as far back as Babylonian times. Instead of trains traveling from point A to point B, though, Babylonians measured canals and weighed stones. Their word problems were practical. You knew why you were learning math, that’s for sure.

Ancient Egyptian teachers teased students with multiplication quizzes and word problems that read something like “There are seven houses, each with seven cats, and each catches seven mice …” Makes your head spin just reading it, doesn’t it?

Word problems confounded students during the Renaissance and through the American Revolution. Plenty of literary giants and everyday comedians have made fun of confusing math practice tests that read more like fantasy novel than a math test.

Modern satirists, like the writers on 'The Simpsons', have produced some famous word problems, and some have found their way into 'Saturday Night Live' sketches as well. Truth told, we all love to hate word problems. But they help us to better understand mathematical concepts and tease out the answers to common problems.

In case you don’t think you’re using word problems in your everyday life, just consider every time you have to leave a tip. How easy is it to express that moment as “My server brought me my meal on time and in good order. Since she did so well, I decided to tip her 20 percent of my bill. When the bill came, I owed $45. How much was my tip?”

So there you go. Word problems are serious business. And so is this math test. Are you ready? Let’s see how you do!

**Tags:** addition, division, drills, math, mathematics, multiplication, subtraction, word problems

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